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Tomtit [17]
3 years ago
10

(How to calculate (-2,8) and (1,6) that =-2/3

Mathematics
1 answer:
Pavel [41]3 years ago
3 0
(6-8)/(1+2)= -2/3 the answer to the question
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-2(x-3) &gt;-8<br> What is the answer
Vlad [161]

Answer:

x < 7

Step-by-step explanation:

First apply the -2 onto each term that it is being multiplied onto.

-2x + 6 > - 8

Now subtract six from both sides.

-2x > -14

Now divide by -2.

x < 7

<u>REMEMBER</u>

When doing greater than and less than equations like this, if you divide by a negative you must flip the greater than/less than.

5 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

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2 years ago
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90000 is divisible by 2
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The answer to your question is D
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Original price $125 discount ? sale price $81.25
levacccp [35]

Answer:(125-81.25)/125 = 0.35 = 35%

Step-by-step explanation:

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3 years ago
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