Answer:
Ta fácil le quedan 5 kilos :v de que grado es esto._.
You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Answer:The LCM of 10, 15, and 20 is 60. After 60 minutes, they ring together again.
Step-by-step explanation:
I ain't Joseph but what's wrong?
Use the Pythagorean Theorem of a² + b² = c² to solve for x.
x² + (x + 3)² = (√117)²
x² + x² + 6x + 9 = 117
2x² + 6x + 9 = 117
2x² + 6x + 9 - 117 = 0
2x² + 6x - 108 = 0
2x² + 18x - 12x - 108 = 0
2x(x + 9) - 12(x + 9) = 0
(2x - 12)(x + 9) = 0
x = - 9, 6
Length cannot be negative so you can't use - 9.
x = 6. Option C is your answer.
