Given:
The quadratic equation is:


To find:
The value of k and
.
Solution:
We have,
...(i)
Putting
, we get




Putting
in (i), we get

Splitting the middle term, we get




Here,
and
.
Therefore, the required values are
and
.
Sorry but where is the picture? I’m confused..
Answer: Varies
Step-by-step explanation:
There would still be some Xs and Ys.
3y = 2x + 6
x + y = 7
y = 7 - x
3(7 - x) = 2x + 6
21 - 3x = 2x + 6
21 - 6 = 2x + 3x
15 = 5x
15/5 = x
3 = x
x + y = 7
3 + y = 7
y = 7 - 3
y = 4
Solution is (3,4)