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coldgirl [10]
3 years ago
13

How do you do this problem?

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Okey so the area of a circle is taken from the equation πr²

now in the sum they have given information as: area of one small circle is 9π

that means :

area of small circle = πr²

= π3²

= π9

so in the sum they have given us the radius of one circle as 3

from this information we understand that the diameter of one small circle should be = 3 ×2

= 6 (as diameter is twice the radius)

we are given 3 of these circles. that means there are 3 times the diameter measured.

so the diameter of the large circle is = 6×3 = 18

as we calculated, since 18 is the diameter of the large circle, it should be taken ½ for radius.

radius of large circle = 18÷2

= 9

now we know the radius of large circle.

taking the equation 'πr²' to find the area:

area of large circle = πr²

= π9²

= π81

your answer is 81π

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Answer:

Mean: \bar x = 40.61

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Step-by-step explanation:

Given

See attachment for data

Solving (a): The mean

Mean is calculated as:

\bar x = \frac{\sum x}{n}

From the attached:

n = 14

So, the mean is:

\bar x = \frac{43.4+43.4+43.4+43.1+43.2+40.2+40.2+40.1+40.3+39.44+39.17+38.03+38.19+36.45}{14}

\bar x = \frac{568.58}{14}

\bar x = 40.61

Solving (b): The median

n = 14; this is an even number. So, the median is:

Median = \frac{1}{2}(n+1)

Median = \frac{1}{2}(14+1)

Median = \frac{1}{2}(15)

Median = 7.5th

This implies that the median is the average of the 7th and 8th item.

Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>

The 7th and 8th items are: 40.2 and 40.2

The median is:

Median = \frac{1}{2}(40.2 + 40.2)

Median = \frac{1}{2}*80.4

Median =40.2

Solving (c): The mode

43.4 has the highest number of occurrence.

So:

Mode = 43.4

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