The third expression is wrong
In the number 14,423, the digit '4' comes up twice, in the thousand and hundred position.
The farther to the left a digit is, the higher that number is compared to another digit to the right of it.
This is why 1,000 is higher than 999.
In the number 14,423, there are two values for four: thousand (four thousand) and hundred (four hundred)
Vertical symmetry because you can cut a square in half vertically and the two parts be exactly the same. Horizontal symmetry because you can cut a square in half horizontally and the two parts be exactly the same. Diagonal symmetry because you can cut the square from corner to corner and the two parts look exactly the same. Rotational symmetry because you can rotate the square and it still look exactly the same. So a square has all of those symmetries. I hope this helped!
SOLUTION
From the given data the mean is 62 and standard deviation is 4
It is required to find the probability that a data value is between 57 and 62
That is:

The z scores is calculated using:

Using the x values it follows:

Also,

Thus the required probability is:
![P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%](https://tex.z-dn.net/?f=P%28-1.25The%20proability%20is%3A%5Btex%5DP%28-1.25This%20can%20be%20expressed%20as%20percentage%20as%3A%5Btex%5DP%28-1.25%5Clt%20z%5Clt0.75%29%3D66.8%5C%25)
Therefore the correct option is C
10 the second power is 10². 10²=10*10=100. 100*18.72=1,872. Hoped I helped. :)