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lara [203]
3 years ago
11

How is adding and subtracting radical expressions similar to adding and subtracting variables ?????

Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0

Answer: To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.

RUDIKE [14]3 years ago
3 0

Answer:

combining like terms. if the radicand is the you can combine the radical. this is the same as combining variables as long as the variable is the same if that makes sense

Step-by-step explanation:

so like you can add 7a and 3a because they have the same variable a. you can combined 2 root 2 and 4 root 2 because the radicand is same <3

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A 2-kg toy car accelerates from 0 to 5 m/s. How much work is done?
Viktor [21]

The work is the difference between the final and initial kinetic energy:

W=\Delta K = \dfrac{1}{2}mv^2_f-\dfrac{1}{2}mv^2_i=\dfrac{1}{2}m(v^2_f-v^2_i)

Substitute your values to get

W=\dfrac{1}{2}\cdot 2(25-0)=25

7 0
4 years ago
Read 2 more answers
Find each quotient. a. 5 ÷ 1/10 B. 5 ÷ 3/10 C. 5 ÷ 9/10
AnnyKZ [126]

Answer:

1. 50

2. 16.6666666667=16.7

3. 5.55555555556=5.6

Step-by-step explanation:

1. 5/0.1=50

2. 5/0.3=16.6666666667=16.7

3. 5/0.9=5.55555555556=5.6

3 0
3 years ago
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What is the next sequence 1/2, 1/2, 3/8, 1/4, 5/32
NemiM [27]
1/8 is tha answer............
5 0
3 years ago
The exterior of a refrigerator is shaped like a rectangular prism, and measures 2 2/3ft wide and 5 1/2 feet high by 2 1/2 feet d
larisa86 [58]
Volume = (2 2/3 ft)*(5 1/2 ft)*(2 1/2 ft)

2 2/3 ft = 8/3 ft
5 1/2 ft = 11/2 ft
2 1/2 ft = 5/2 ft

Volume = (8/3)*(11/2)*(5/2)
Volume = (88/6)*(5/2)
Volume = (440/12) = 36 8/12 = 36 2/3

<u><em> . . . Volume = 36 2/3 ft³</em></u>


7 0
3 years ago
oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters. determine the density of oak in grams per cubic cen
bogdanovich [222]

Answer:

The density of oak is <u>0.695</u> grams per cubic centimeter.

Step-by-step explanation:

Given:

Oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters.

Now, to find the density of oak in grams per cubic centimeter.

Mass (m) = 2.85 kilograms.

So, using conversion factor we convert into grams:

2.85\times 1000=2850\ grams.

Volume (v) = 4100 cubic centimeters.

Now, to get the density by using formula:

Density=\frac{mass}{volume} \\Density=\frac{m}{v}

Density=\frac{2850}{4100}

Density=0.695\ grams\ per\ cubic\ centimeter.

Therefore, the density of oak is 0.695 in grams per cubic centimeter.

6 0
3 years ago
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