Hello! And thank you for your question!
First we are going to redo the equation:
<span><span><span>y<span><span>^3</span><span></span></span></span>−3<span>y^<span><span>2</span><span></span></span></span>(3)+3(y)×<span>3<span><span>^2</span><span></span></span></span>−<span>3<span><span>^3</span><span></span></span></span>=0
Then we are going to use Cube of Difference:
0 = (y - 3)^3
That take cube root of both sides:
0 = y - 3
Finally add 3 to both sides:
3 = y
Final Answer:
y = 3</span></span>
To find mean all you have to do is add all the numbers up and divide ny how many numbers there are. If you add them all together is equals 1295. now divide that number by the amount of numbers there are which is 10, and divide 1295 by 10. You get 129.5
Answer:
The axis of symmetry will be at 1
Step-by-step explanation:
The middle of -3 and 5 will be the axis :)
-3, -2, -1, 0, 1, 2, 3, 4, 5
-2, -1, 0, 1, 2, 3, 4
-1, 0, 1, 2, 3
0, 1, 2
1
Answer:
x = 4 ±√26
Step-by-step explanation:
Please write this as x^2 - 8x = 10, or x^2 - 8x - 10 = 0. " ^ " indicates exponentiation.
Let's complete the square:
x^2 - 8 x can be rewritten as
x^2 - 8x + 16 - 16, and so
x^2 - 8x = 10 becomes x^2 - 8x + 16 - 16 - 10 = 0, or
(x - 4)^2 = 26
Taking the square root of both sides, we get:
x - 4 = ±√26, or
x = 4 ±√26
