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Leviafan [203]
3 years ago
9

How do I solve -x^2+7x-3=0

Mathematics
1 answer:
poizon [28]3 years ago
6 0
-x^2+7x-3=0 multiply the expression by -1

x^2-7x+3=0  we will complete the square so subtract 3 from both sides

x^2-7x=-3  now halve the linear coefficient, -7/2, square it 49/4, and add that to both sides...

x^2-7x+49/4=49/4-3  now the left side is a perfect square...

(x-7/2)^2=(49-12)/3

(x-7/2)^2=37/3  take the square root of both sides...

x-7/2=±√(37/3)  now add 7/2 to both sides...

x=7/2±√(37/3)
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