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zzz [600]
4 years ago
7

Which is the correct standard notation for 9.3 x 10^5 9,300 93,000 930,000 9,300,00

Physics
2 answers:
ella [17]4 years ago
7 0
The correct standard notation for 9.3x10^5 is 930,000.
ryzh [129]4 years ago
3 0

Answer:

930,000

Explanation:

9.3 x 10^5

The power of 10 (5 in this question) gives the number of times the decimal point is to be moved to the right.

If there was a negative sign in front of the power, the number would have been an indication of how many times the decimal point is to be moved to the left.

Further to this

9.3 x 10^5 = 9.30000000 x 10^5

= 930000.000

= 930,000

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A uniformly charged conducting sphere of 1.1 m diameter has a surface charge density of 6.2 µC/m2. (a) Find the net charge on th
ira [324]

Answer:

(a) q = 2.357 x 10⁻⁵ C

(b) Φ = 2.66 x 10⁶ N.m²/C

Explanation:

Given;

diameter of the sphere, d = 1.1 m

radius of the sphere, r = 1.1 / 2 = 0.55 m

surface charge density, σ = 6.2 µC/m²

(a)  Net charge on the sphere

q = 4πr²σ

where;

4πr² is surface area of the sphere

q is the net charge on the sphere

σ is the surface charge density

q = 4π(0.55)²(6.2 x 10⁻⁶)

q = 2.357 x 10⁻⁵ C

(b) the total electric flux leaving the surface of the sphere

Φ = q / ε

where;

Φ is the total electric flux leaving the surface of the sphere

ε is the permittivity of free space

Φ = (2.357 x 10⁻⁵) / (8.85 x 10⁻¹²)

Φ = 2.66 x 10⁶ N.m²/C

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3 years ago
What do an earthquake wave and a light wave have in common?
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A 10.0 kg weather rocket generates a thrust of 230 NN . The rocket, pointing upward, is clamped to the top of a vertical spring.
blondinia [14]

Answer: 0.2m

Explanation: Firstly only the Rocket's Weight Compress the spring which can be found by

F_r=M_r*g\\F_r=10*9.81\\F_r=98.1N

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F_r=k*x\\x=F_r/k\\x=98.1/480\\x=0.2m

The part b and c of this question is done in the attachment

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How to find coefficient of lift from coefficient of pressure?
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Ramas weight is 40 kg. She is carrying a load of 20 kg up to a height of 20 m. What work does she do? What work does she do?
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Answer:

The work done by Ramas is 3920 N.

Explanation:

Given;

mass of the load lifted by Ramas, m = 20 kg

height through which the load is lifted, h = 20 m

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