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dlinn [17]
3 years ago
10

The speed of light in cubic zirconia

Physics
1 answer:
schepotkina [342]3 years ago
6 0

The index of refraction for the cubic zirconia at the given speed of light is 2.16.

The given parameters:

  • <em>Speed of light in Cubic zirconia, v = 1.39 x 10⁸ m/s</em>
  • <em>Speed of light in air, c = 3.0 x 10⁸ m/s.</em>

The index of refraction for the cubic zirconia is the ratio of the speed of light in air to speed of light in cubic zirconia and it is calculated as follows;

\eta = \frac{c}{v} \\\\\eta = \frac{3\times 10^8}{1.39 \times 10^8} \\\\\eta = 2.16

Thus, the index of refraction for the cubic zirconia at the given speed of light is 2.16.

Learn more about index of refraction here: brainly.com/question/10729741

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8 0
3 years ago
Solve:40KMEN
Oksanka [162]

The spider will cross the driveway <u>25.71 in seconds</u>.

Why?

It's a conversion problem, so, in order to solve it, we need to convert the units of the given information.

Let's convert the given speed (in cm/s) to m/s.

We know that:

1m=100cm

So, converting we have:

14\frac{cm}{s}*\frac{1m}{100cm}=0.14\frac{m}{s}

Then, calculating the time, we have:

distance=speed*time\\\\3.6m=0.14\frac{m}{s}*time\\\\time=\frac{3.6m}{0.14\frac{m}{s}}=25.71s

We have that the spider will cross the driveway in 25.71 seconds.

Have a nice day!

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