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aleksley [76]
3 years ago
5

3 points

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

Potential

Explanation:

The water in the bathtub has more potential energy than that in the tea cup because it has a greater number of water molecules.

Mass is a parameter that is very instrumental in determining potential energy.

The potential energy of a body is the energy due to the position of that body.

   Potential energy  = mass x acceleration due gravity x height

Mass is the amount of matter in a substance. Water in the tub will have more mass and contain a greater number of water molecules there in.

Since potential energy is directly proportional to mass, then, it will have a greater amount of potential energy.

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A contact force is a force that is exerted by an object when it touches another object. Which of the following is an example of
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Ummmm....... i think it's b 
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3 years ago
You need to estimate the floor area of your unusual oval shaped living room from memory you remember that it is longer than wide
REY [17]

Answer:

Our estimate not done correctly because the width was unrealistic.

Explanation:

Given that,

Length = 6 m

Width = 0.5 m

We need to calculate the area of rectangular floor

Using formula of area

A=l\times w

Where, l = length

w= width

Put the value into the formula

A=6\times0.5

A=3\ m^2

We need to find why this estimate not done correct

Using given data

We can say that,

We assume width was unrealistic.

The length of room is 6 m.

We know that,

1\ m=3.28\ feet

So, the length would be 20 feet.

The width of room is 0.5 m.

The width of room would be 1.64 feet.

So, the area will be

A=20\times1.64

A=32.8\ feet^2

Hence,  Our estimate not done correctly because the width was unrealistic.

4 0
3 years ago
A charge of 4 nc is placed uniformly on a square sheet of nonconducting material of side 17 cm in the yz plane. (a) what is the
Ratling [72]

The charge density of the sheet is 1.384×10⁻⁷C/m².

Charge density is defined as the charge per unit area.

The sheet is a square of length  l=17 cm.

Calculate the area A of the sheet .

A=l^2=(17 cm)^2= (17*10^-^2m)^2=0.0289 m^2

The charge Q on the sheet is

Q=4nC=4*10^-^9C

The charge density σ is given by,

\sigma=\frac{Q}{A}

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>

8 0
4 years ago
what is the rate of acceleration of a 2,000-kg truck if a force of 4,200n is used to make it start moving forward
Basile [38]
I have concluded that the formula for this equation would be F = ma, therefore the equation would look like this:


F = ma
F = 4,200n/ 2,000 kg
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The rate of acceleration is 2.1, hopefully I this will be of assistance to you. :)
8 0
3 years ago
Sally and ner pet puagie go everywnere
FrozenT [24]

a)The total distance she walks will be 1100 m.

b)The magnitude and direction of the budgie's path will be 854.4 m at 69.44°.

c)Sally's average speed for the journey will be 2.82 m/sec

d)The average velocity of Sally's budgie willl be 2.19 m/sec North of East.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points.

Distance travelled in north direction,d₁ = 8.0 x 10² m

Time elapsed  travelled in north direction,t₁ = 5.0 minutes

Distance travelled in east direction,d₂ = 0.30 km = 3.0 × 10² m

Time elapsed  travelled in east direction,t₂= 1.5 minutes

The total distance she walks,d =? m

The magnitude and direction of the budgies path will be, D

Sally's average speed for the journey, \rm S_{avg}

The average velocity of Sally's budgie,\rm V_{avg}

a)

The total distance she walks is found as;

d=d₁+d₂

d=800 m +300 m

d = 1100 m

b)

The magnitude and direction of the budgies path will be;

\rm D = \sqrt{d_1 ^2 + d_2^2 } \\\\ D = \sqrt{800^2 +300^2 } \\\\ D = 854.4 \ m

The direction of the displacement is;

\rm   \theta  = tan^{-1} \frac{800}{300} \\\\ \theta = tan^{-1}(2.6) \\\\ \theta = 69.44 ^ 0

c)journey is found as;

Sally's average speed for the

\rm S_{avg}  = \frac{d}{t} \\\\  S_{avg}  =\frac{100}{300+900} \\\\  S_{avg}  =2.82 \ m/sec<em>
</em>

d)

The average velocity of Sally's budgie is found as;

\rm V_{avg}  = \frac{854.4}{300+ 900 } \\\\ V_{avg}  = 2.19 \ m/sec North of east

Hence, the total distance she walks, the magnitude and direction of the budgie's path, Sally's average speed, and the average velocity of Sally's budgie will be 1100 m,854.4 m at 69.44°,2.82 m/sec, and 2.19 m/sec North of East.

To learn more about displacement refer to the link;

brainly.com/question/10919017

#SPJ1

6 0
2 years ago
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