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sergey [27]
3 years ago
6

Help please I do not get this problem at all

Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

It should be 4. The ratio that AC is equal to DE at should be equal to the ratio of BE to BC. If you want an explanation I'd be happy to add one!

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Question #2 What is the difference?​
e-lub [12.9K]

Answer:

B  \frac{b-10}{b-1}

Step-by-step explanation:

In order to get the same denominator, we need to multiply the second fraction by (b+2) in the numerator and denominator.

We will end up in something like this :\frac{b^{2} - 2b - 8 -6(b+2) }{(b-1)(b+2)}

I just timed the second fraction by b+ 2 and then i added them together.

Therefore, we will get \frac{b^{2} - 8b - 20}{(b-1)(b-2)}

now factoring the numerator we will end like this

\frac{(b-10)(b+2)}{(b-1)(b+2)}

we will then end up with the answer.

Hope this helps.

3 0
3 years ago
Simplify 4sqrt6/sqrt30 by rationalizing the denominator
andreev551 [17]
4sqrt5/5

see the attachment

8 0
3 years ago
Solving a Multi-Step Equation
VLD [36.1K]

Answer:

x = 15

Step-by-step explanation:

I have this all put under a photo. Let me know if you need any explanation

5 0
3 years ago
Read 2 more answers
the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that
jolli1 [7]

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

5 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for the line containing the giving points (10,2) (2,-2)
zysi [14]

(y - yo) = m.(x - xo)

(-2 - 2) = m.(2 - 10)

-4 = m.(-8)

m = -4/-8

m = 1/2

(y - yo) = 1/2.(x - xo)

(y - 2) = 1/2.(x - 10)

y - 2 = 1/2x - 5

y = 1/2x - 5 + 2

y = 1/2x - 3

7 0
3 years ago
Read 2 more answers
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