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2 years ago

Positive, negative, zero or undefined?

Mathematics

2 answers:

Liula [17]2 years ago

4 0

Answer:

Negative.

Step-by-step explanation:

Hope this helps.

zalisa [80]2 years ago

3 0

Positive / that’s what positive looks like lamsososos

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Please this is my last point I really need help <br> Show workings

Lisa [10]

Answer:

x = 14.375

Step-by-step explanation:

Ok, so we know that a triangle has a total interior degree of 180°. And since we already have a 95° angle, we just need to subtract 95 from 180.

180° - 95° = 85°

Now, we already have indicators that two of the three sides are equal. And we already got the angle of the side that does not have a matching partner. So we just need to divide what we already have by 2.

85° / 2 = 42.5°

Now that we know each side is 42.5 degrees, we just need to grab our given equation and put and equal sign at the end with what we already know is the answer (since we are trying to solve for <em>x</em>).

(4x - 15) = 42.5

Now, let's just get rid of those useless parentheses.

4x - 15 = 42.5

Next, we just need to have the variable on its own side, all by itself. So, in order to do that, we just add 15 to both sides.

4x = 57.5

Now, for our final step, we just need to divide each side by our variables' factor (which is a positive 4). In which we get our final answer of:

x = 14.375

4 0

3 years ago

Read 2 more answers

Plz help loves i need

Ratling [72]

Answer:

It's the letter B :)

5 0

2 years ago

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Let B be the basis of P3 consisting of the Hermite polynomials in Exercise 21, and let p.t / D 7 ! 12t ! 8t 2 C 12t 3. Find the

Anastasy [175]

To calculate the relative vector of B we have to:

$P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]$

The coordenates of:

$p(t)= 12t^3-8t^2-12t+7$ , with respect to B satisfy:

$C_1(1)+C_2(2t)+C_3(-2+4t^2)+C_4(-12t+8t^3)= 7-12t-8t^2+12t^3$

Equating coefficients of like powers of t produces the system of equation:

$\left \{ {C_1-2C_3=7} \atop {2C_2-12C_4=-12} \right. \\\left \{ {{4C_3=-8} \atop {8C_4=12}} \right.$

After solving this system, we have to:

$C_1=3\\C_2= 3\\C_3= -2\\C_4= \frac{3}{2}$

And the result is:

$P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]$

Learn more: brainly.com/question/16850761

4 0

3 years ago

Which line from “Raymond's Run” is evidence that Squeaky has courage?

likoan [24]

Answer:

when squeaky stands up to the mean girls

Step-by-step explanation:

6 0

3 years ago

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Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane

storchak [24]

Answer:

$f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)$

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

$f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)$

Note that

$f(0) = (1,0,-1)$
$f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})$

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0

3 years ago