335/1000 if you read it out loud .335 is three hundred fifty-five thousandths
Only option 1 and 4 are true.
Points S, U, and T are the midpoints of the sides of ΔPQR.
ΔSUT is inside of ΔPQR. Points S, U, and T are the midpoints of ΔPQR.
Which statements are correct? Check all that apply.
1. QP = UT
2. One-halfTS = RQ
3. SU = PR
4. SU ∥ RP
5. UT ⊥ RP
Given to us,
S, U, and T are the midpoints of the sides of ΔPQR.
Using Triangle Midpoint Theorem, which states that the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.
Therefore, only option 1 and 4 are true.
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once you figure out which is lthe length and which is the width you would multiply the two together and you wold get your area of the rectangle which sould be 0.322 meters
Answer:
g(x) = -3(8 - x)² + 2x
g(-3) = -3(8 - (-3))² + 2(-3)
g(-3) = -3(11)² - 6
g(-3) = -33² - 6
g(-3) = -1089 - 6
g(-3) = -1095
If I got something wrong, then I'm sorry, but I believe that this is all correct.
The value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10. Option C
<h3>How to determine the value</h3>
It is important to note that for line TV to be parallel to line QS, the sides of the triangle must be divided equally.
Thus, we have
RT/TQ = RV/VS
RT = x + 10
TQ = x - 3
RV = x + 10
VS = x
Substitute the value
Cross multiply
(x+ 4) × x = (x + 10) × (x-3)
x² + 4x = x² -3x + 10x -30
Divide through by x²
4x = -3x + 10x - 30
Collect like terms
4x + 3x - 10x = - 30
-3x = -30
x = -30/ -3
x = 10
Thus, the value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10 Option C
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