PLZ HELP Given quadrilateral ABCD, if diagonals AC and BD bisect each other, and angle ABC=91°, but you know nothing about any l engths in the diagram, what special figure MUST ABCD be? A rhombus or a parallelogram? HOW DO YOU KNOW.
1 answer:
Answer:
A parrallelogram
Step-by-step explanation:
It would be a rhombus because when the 2 diagnols bisect eachother, angle b =91, so that means b would be half of that and all angles in rhombus are equal i tink. I am in 7th grade so idk but that is what i think.
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Answer:
(-5,6)
Step-by-step explanation:
G(-5,4)=(x1,y1)
H(-5,8)=(x2, y2)
midpoint=?
now,
(x,y)= x1+x2/2 y1+y2/2
-5-5/2 4+8/2
-10/2 12/2
-5 6
therefore the co ordinates of midpoint are(-5,6)
Answer:
B) -3/10 x -6
Step-by-step explanation:
-3/10 x -6=-3 x -6/10
When multiplying two negatives you get a positive.
Hope this helps :)
Answer:
-27 = q
Step-by-step explanation:
I am not sure that my answer is correct but hopefully that helps.
Probability a gets a head = 1/2
