Substract '-3.4x' at LHS nad the RHS of the above expression.
Add '4' on both LHS and RHs of the above expression.
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But its still not that much info what is the answers for it if there is no answer
How are you finding what does x equal
Answer:
D.3.5
Step-by-step explanation:
4x+2y=10(given)
2x+y=5
y=5-2x-----(1)
y=2x-1------(2)(given)
Since the left side of the equations are the the same,
5-2x=2x-1
4x=6
x=1.5
Sub x=1.5 into eq(1),
y = 5-2(1.5) = 5-3 = 2
so, x+y = 1.5+2 = 3.5
He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix?
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>
<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>
<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
