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daser333 [38]
3 years ago
15

A*4=e b\4=e c+4=e d-4=e A+b+c+d=100

Mathematics
1 answer:
ratelena [41]3 years ago
4 0
I believed you are looking for the value of e. The value of e is 16 below is the solution:

A×4 = E, so A=E/4
B/4 = E, so B=4E
C+4 = E, so C=E=4
D-4 = E, so D=E+4
and
A+B+C+D=100.

Substitute values of A, B, C and D in the equation, we get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
<span>E = 16</span>
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Step-by-step explanation:

In ∆ABC

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We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

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∴ Δ ACD is an isosceles triangle

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- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

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∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

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