3 years ago

Express the product of 2x^2+6-8 and x+3 in standard form

1 answer:

7 0

Answer:2x3+12x2+10x−24Explanation:The product of these expressions 'means' to multiply them. hence : (x + 3 )(2x2+6x−8) Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be achieved as follows.x(2x2+6x−8)+3(x2+6x−8[2x3+6x2−8x[6x2+18x−24]=2x3+6x2−8x+6xx−24 collect 'like terms'=2x3+12x2+10x−24 is in standard form

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VARVARA [1.3K]

y = -7(-13)

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Use the trig ratio cosine because you are given the adjacent leg and the hypotenuse.

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Shalnov [3]

Our inequality looks like this:
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