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3 years ago

1+2+3+4+5+6.......+99 what is the quickest way to find the answer Thank u

Mathematics

2 answers:

Furkat [3]3 years ago

8 0

$1+2+3+4+5+6+\ldots+99=\\(1+99)+(2+98)+\ldots+(49+51)+50=\\49\cdot100+50=\\4950$

serious [3.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

Use the formula Sum = (a + L)*n/2

The tricky part is n. That's the number of terms between 1 and 99 inclusive.

n = 99 -1 + 1 = 99

n = 99

a = 1

L = 99

Sum = (1 + 99)*99 / 2

Sum = (100)*99/2

Sum = 4950

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

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Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

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Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

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$\displaystyle y = \sqrt{x - 3}$

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Step 3: Solve

Find coordinates

x-coordinate

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[Multiplication Property of Equality] Multiply √(x - 3) on both sides: $\displaystyle \sqrt{x - 3} = 1$
[Equality Property] Square both sides: $\displaystyle x - 3 = 1$
[Addition Property of Equality] Add 3 on both sides: $\displaystyle x = 4$