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Naily [24]
3 years ago
10

15 POINTS PLLLSSS HELP

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

C) decreasing when x > –1

Step-by-step explanation:

To determine whether a function is increasing or decreasing, or whether it increases or decreases in an interval, you must look at the function or the interval from left to right.

Start at the left and move to the right. You see that the function (the y-coordinate of each point) is increasing from an v value of negative infinity till x = -1. At x = -1 the function reaches a maximum point. Now start at x = -1 and, moving to the right, the value of the function (the y-coordinate of each point) decreases.

The correct answer is C) decreasing when x > –1

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Can some show the work for this problem.
Nostrana [21]
What problem is there to show work for?
4 0
3 years ago
What is x and y using substitution
Bad White [126]
X-5y=36
x+y=-26

y=-26-x

x-5(-26-x)=36
x+130+x=36
2x+130=36
2x=36-130
2x=-94
x=47
5 0
4 years ago
Read 2 more answers
Which of the following is the balance for a single $3,200 deposit in an account with an APR of 2.6% that compounds interest quar
Flauer [41]

Answer:

FV= 3200(1+\frac{0.026}{3})^{3(6)}=3200 (1.008667)^{54}= 50994.590

Step-by-step explanation:

For this case we can use the formula for the future value with compound interest given by:

FV= P (1+\frac{r}{n})^{nt}   (1)

For this case since the interest is compounded quarterly we have 3 periods each year, since we have 3 quarters in a year.

r represent the rate =0.026

t = 6 represent the number of years

P = 3200 represent the amount invested at the begin

If we apply the formula (1) we got:

FV= 3200(1+\frac{0.026}{3})^{3(6)}=3200 (1.008667)^{54}= 50994.590

So then the balance after 6 years would be approximately 50995 with the conditions provided.

7 0
3 years ago
The x intercept of a line is -5 and the y intercept of the line I’d -2.what is the equation of the line?
Ivan

Hey!

There are two ways to solve this problem, I have showed you both of them below:

Method 1 -:

So we know that the x-intercept of the line is at (-5,0) and the y-intercept is at (0,-2). The most common form of the equation of a line is the slope-intercept form which is written as y=mx+b. In this equation, y and x are two points on the line, m is the slope and b is the y-intercept.

We are given the value of b which is -2. We also know two points on the line so we can find the slope. The formula for slope is (y2-y1)/(x2-x1). We can now plug in the points into the equation and get (0-(-2)/(-5-0). This simplifies to -2/5. That is your slope.

Now that we know this, we have solved for everything we need for writing the equation of the line. The equation of the line is:

y = (-2/5)x - 2

Method 2 -:

This method is a bit easier but will still give you the same result. Since you already know the y-intercept as -2, you know the value of b. You also have atleast one point so you can just plug it into the equation y = mx + b.

Now you can just plug in a point for x and y. We also know the x-intercept and that might be easier to use for solving. The x-intercept is (-5,0) and we can plug this into the equation to get 0 = m(-5) + (-2). We can now rewrite this as 0 = -5m - 2.

The next thing we do is solve for x:

0 = -5m - 2

2 = -5m

-2/5 = m

Now we know that m = -2/5, we can put this into the equation along with the y-intercept to get our answer.

y = (-2/5)x - 2

6 0
3 years ago
Spencer sampled 50 students of a private school who were questioned about their scores in Mathematics. Spencer wants to test the
pickupchik [31]

Answer:

C) 3.03

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given sample size 'n' = 50

The Mean of the population (μ) = 62

The standard deviation of the Population (σ) = 7

Mean of the sample(x⁻) = 65

Z-score

                 Z= \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

<u><em> Step(ii):-</em></u>

<em>                </em>Z= \frac{65 -62}{\frac{7}{\sqrt{50} } }<em></em>

<em>               Z =  3.03</em>

<u><em>Final answer:-</em></u>

<u><em>The Z-score = 3.03</em></u>

6 0
3 years ago
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