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3 years ago

If asked to solve an oblique triangle and you are given only the three angles, it would be best to use the Law of Cosines.

Mathematics

1 answer:

Art [367]3 years ago

6 0

The answer is trueeee

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50 points!!! Find the 4 arithmetic means between -3.2 and 5.8. List answer with all numbers, state the common difference, and sh

emmainna [20.7K]

Answer:

{-3.2, -1.4, 0.4 2.2, 4.0, 5.8}
common difference: 1.8

Step-by-step explanation:

The difference between the two numbers is ...

5.8 -(-3.2) = 9

The four "means" divide this interval into 5 parts, so each part has a length of ...

9/5 = 1.8 . . . . the common difference

The values of the "means" can be found by adding 1.8 successively:

-3.2 +1.8 = -1.4

-1.4 +1.8 = 0.4

0.4 +1.8 = 2.2

2.2 +1.8 = 4.0

Including the given numbers, the arithmetic sequence is ...

-3.2, -1.4, 0.4, 2.2, 4.0, 5.8 . . . . . common difference of 1.8

5 0

3 years ago

What is the value of this expression?<br><br> (−8) to the 3rd power

slamgirl [31]

$(-8)^3=(-8)\cdot(-8)\cdot(-8) = -512$

7 0

3 years ago

PLEASE HELP ASAP I NEED THIS LIKE RIGHT NOW NO LINKS OR WILL BE REPORTED! SHOW ALL OF YOUR WORK! 3. The area of the square rug i

kondaur [170]

Answer:

well,

it's more than (20ft)²

bc 20*20 =400

21² = 21 * 21 = 441

getting closer...

22² = 22 * 22 = 484

$\sqrt{484} = {22}^{2}$

yet, we arrived, short trip tough, pls leave the bus in an orderly manner

4 0

3 years ago

3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶<br>

BARSIC [14]

Answer:

$\dfrac{3^{13}}{2}$

Step-by-step explanation:

Given expression:

$\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}$

$\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:$

$\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}$

$\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}$

$\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}$

$\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies 3^{(19-6)} \cdot 2^{(5-6)}$

$\implies 3^{13} \cdot 2^{-1}$

$\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:$

$\implies \dfrac{3^{13}}{2^1}$

$\textsf{Apply exponent rule} \quad a^1=a:$

$\implies \dfrac{3^{13}}{2}$

4 0

2 years ago

1.4 – ( ___ ) = 2<br> Pls hurry plz

Zigmanuir [339]

The answer should be -0.6

8 0

3 years ago

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