we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Umm. Where is the question?
Answer:
Step-by-step explanation:
I think you are to assume that this is a trapezoid and that the top right angle symbol is missing.
Area = (b1 + b2 ) * h /2
Givens
b1 = 2
b2 = 6.2
h = 3
Solution
Area = (2 + 6.2)* 3 / 2 Combine what is inside the brackets
Area = 8.2 * 3 / 2 Divide by 2
Area = 4.1 * 3 Combine
Answer: Area = 12.3
Answer.com download the app or better yet look for a version like that on google
Number of 1 inch cubes:
Volume of the 1 inch cubes = 1*1*1 = 1 cubic inches.
Volume of the 5 inch cubes = 5*5*5 = 125 cubic inches.
Number = Volume of the 5 inch cubes / Volume of the 1 inch cubes
= 125 /1 = 125.
125 of the 1-inch cubes.