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KatRina [158]
4 years ago
9

............... help :)????????????????

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
4 0

Answer:

A

Step-by-step explanation:

We graph two variable inequalities like we graph line equations. First, read the inequality as y\geq mx+b where m is the slope and b is the y-intercept. Here b= 2. Go to the y-axis and mark a point on 2. From here, go up 3 and over 2. Mark the point at (2, 5).  Since the inequality does not have an "equal to" draw a dashed line is drawn between the points with arrows on either end. To finish, test an (x,y) point to determine what makes the inequality true.  

Choose any (x,y) point not on the line. Say (0,0).

y < \frac{3}{2}x + 2\\0

Is the statement true? Yes. This means shade this side of the line.

Solution A matches this.

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Simplify the product.
liberstina [14]

The value of the product expression is –6p^3 + 8p^2 – 10p

<h3>How to simplify the product?</h3>

The product expression is given as:

2p(–3p2 + 4p – 5)

Rewrite properly as:

2p(–3p^2 + 4p – 5)

Remove the bracket

2p * –3p^2 + 2p * 4p – 2p * 5

Evaluate the products

–6p^3 + 8p^2 – 10p

Hence, the value of the product expression is –6p^3 + 8p^2 – 10p

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2 years ago
Reason abstractly, Evaluate each expression: |13 - 6| = ____
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Answer:

7

Step-by-step explanation:

13-6=7 the other line doesn't affect the answer because it isn't negative

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Function f is shown on the graph. What is the range of f?
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Answer:

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Step-by-step explanation:

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Determine whether the sequence converges or diverges. if it converges, find the limit. (if an answer does not exist, enter dne.
Arada [10]

The sequence a_n=\frac{n^2}{n^3+5n} diverges.

For given question,

We have been given a sequence a_n=\frac{n^2}{n^3+5n}

We need to determine whether the sequence converges or diverges.

From given sequence we have, a_{n+1}=\frac{(n+1)^2}{(n+1)^3+5(n+1)}

We use Ratio Test.

According to Ratio Test, r=\frac{a_{n+1}}{a_n}, where sequence converges if and only if |r| < 1.

Consider,

\lim_{n \to \infty} |\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(n+1)^2}{(n+1)^3+5(n+1)}}{\frac{n^2}{n^3+5n}} |\\\\\\= \lim_{n \to \infty} |\frac{(n+1)^2(n^3+5n)}{n^2[(n+1)^3+5(n+1)]} |\\\\=\infty

Since \lim_{n \to \infty} |\frac{a_{n+1}}{a_n} | is not defined, the sequence a_n=\frac{n^2}{n^3+5n} diverges.

Therefore, the sequence a_n=\frac{n^2}{n^3+5n} diverges.

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