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3 years ago

What do you think the answer is, Hurry

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

The answer is probably (a).

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What is the Area of the shaded portion in the square.

riadik2000 [5.3K]

Step-by-step explanation:

Area of the squre is pi -360/2

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3 years ago

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and

defon

The expression that can be used to approximate the expression below is $log_a x = \frac{log_{b}a}{log_{b}x}$

Given the logarithmic function expressed as $log_a x$ , we need the log expression that is equivalent to the given expression.

To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;

$log_a x = \frac{log_{10}a}{log_{10}x}$

This is similar to the option c where the base of "b" was used as $log_a x = \frac{log_{b}a}{log_{b}x}$

Learn more on law of logarithms here: brainly.com/question/11587706

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2 years ago

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Dimas [21]

Jssjsjsjsjsjdjidjebsvabbxjxjufiwiwj .

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3 years ago

Read 2 more answers

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago

Line segment AB is drawn in the coordinate plane. Carlos graphed the set of points that are the same distance from both point A

Illusion [34]

Answer:

Carlos graphed the perpendicular bisector of AB.

Step-by-step explanation:

Given a line segment AB drawn in a coordinate plane. The set of points that are the same distance from points A and B divides the line segment AB into two equal parts.

This line is referred to as the perpendicular bisector of AB.

Therefore, Carlos graphed the perpendicular bisector of AB.

6 0

3 years ago