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uranmaximum [27]
3 years ago
8

Lynn Margulis developed the endosymbiont theory to explain the evolution of certain eukaryote organelles, such as chloroplast an

d mitochondria. According to this theory which of these events occurred to anvient prokaryote cell?

Biology
1 answer:
Flura [38]3 years ago
6 0

Answer:

The answer is C. The cell took in another ancient prokaryotic cell, which began living inside it.

Explanation:

  • The Endosymbiont Theory explains the evolution of membrane bound organelles such as mitochondria and chloroplasts.
  • According to the theory, mitochondria evolved when an ameoba like organism engulfed bacteria capable of cellular respiration.
  • Similarly, chloroplasts were developed when the ameoba like organism engulfed cyanobacteria or blue-green algae capable of photosynthesis.
  • These organisms survived inside the ameoba over millions of years to develop into mitochondria and chloroplasts.
  • The fact that mitochondria and chloroplasts have their own circular DNA and ribosomes is evidence of the endosymbiont theory.
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Answer:

I - Interphase

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Milk - Metaphase

And - Anaphase

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2 years ago
Before replication can take place.(1) A. DNA polymerases must add complementary nucleotides to DNA. B. the two strands of DNA mu
andriy [413]

Answer:

The correct answer is B. the two strands of DNA must separate.

Explanation:

DNA is a double-stranded structure. The two strands are joined together by the formation of hydrogen bonds between complementary nucleotides. So before the replication takes place these two strands must be separated.

The separation of DNA strand is accomplished by the action of a helicase enzyme which breaks the hydrogen bond between complementary nucleotides and separated the two DNA strands.  

After separation, the DNA polymerase binds to separated DNA and replicating the DNA. So the right answer is B.

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3 years ago
Describe what is happening in terms of atoms and bonds in this chemical reaction
erica [24]

The atoms are going through decomposition.They are breaking apart into the elements they are made of.

3 0
3 years ago
The table provided shows the predator-and-prey relationships in a wetland habitat.
cupoosta [38]

Answer:

mosquitoes

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7 0
3 years ago
If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of th
Sergio [31]

Answer:

If an inhibitory synapse fires at the same time and at the same distance from the initial segment as an excitatory synapse of the same intensity there will be no changes in the potential in the firing zone.

Explanation:

Under normal conditions, the transmembrane potential depends on the ionic charges present in the intracellular and extracellular spaces. The extracellular space load is usually positive and in the cytoplasm is negative.

  • <u>Depolarization</u> occurs by opening ion channels that allow sodium to enter the cell, making the intracellular space more positive.
  • An opening of potassium channels releases this ion to the extracellular space, leading to <u>hyperpolarization</u>.

An excitatory synapse is one capable of depolarizing a cell and boosting the production of action potential, provided it is capable of reaching the threshold of said potential.

On the other hand, an inhibitory synapse is able to hyperpolarize the cell membrane and prevent an action potential from originating, so that they can inhibit the action of an excitatory synapse.

The interaction between two synapses, one excitatory and one inhibitory, -called synapse summation- will depend on the strength that each of them possesses. In this case, the intensity of both synapses being the same, there will be no changes in the membrane potential in the firing zone.

Learn more:

Excitatory and inhibitory postsynaptic potentials brainly.com/question/3521553

6 0
3 years ago
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