Plot the y-intercept (0,-1) and then from that point go up seven and to the right one. Plot that point, then draw the line between the two points.
Hope this helped! Good luck! :)
Answer:
The equation of a line through (5 -3) that is parallel to y = 1/2 x+3 is
y = - 2 x + 7
Step-by-step explanation:
Let us assume the slope of the line whose equation we need to find is m 1.
The line parallel to the needed line is: y=1/2x+3
Comparing it with the general form: y = m x + C
we get m 2 = 1/2
Now, as Line 1 is Perpendicular to Line 2.
⇒ m 1 x m 2 = -1
⇒ m 1 x ( 1/2) = -1
⇒ m 1 = - 2
Also, the point son the line 1 is given as: (x,y) = (5,-3)
Put the value of point and Slope in y = m x + C to find the value of Y- INTERCEPT.
we get: -3 = (-2) (5) + C
or, C = -3 + 10 = 7
⇒ C = 7
The general line equation is given as: y = m x + C
Substituting the values of C and m, we get:
y = - 2 x + 7
Hence, the equation of a line through 5 -3 that is parallel to y = 1/2 x+3 is
y = - 2 x + 7
Answer:
<em>(-6, 0) and (0, 1.5)</em>
<em></em>
Step-by-step explanation:
The equation of the line in pint slope form is expressed as;
y-y0= m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given
m = 1/4
(x0, y0) = (6,3)
Substitute into the formula;
y - 3 = 1/4(x-6)
4(y-3) = x - 6
4y - 12 = x-6
4y - x = -6+12
4y - x = 6
x = 4y - 6
To get the points to plot, we will find the x and y-intercept of the resulting expression.
For the x-intercept,
at y = 0
x = 4(0) - 6
x = -6
Hence the x-intercept is at (-6, 0)
For the y-intercept,
at x = 0
0 = 4y - 6
4y = 6
y = 6/4
y = 3/2
y = 1.5
Hence the y-intercept is at (0, 1.5)
<em>Hence the required points to plot to get the required line are (-6, 0) and (0, 1.5)</em>
<em></em>
In order to answer this problem, you need to remember the place – value chart since you don't want to convert the number to its standard form. The number "fifty million" has nine places. Enumerating from the left would be:
<span>- Ones - Tens - Hundreds - Thousands - Tens thousands - Hundreds thousands - Millions - T<span>ens millions</span></span>