Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
what do u need help with lol
Step-by-step explanation:
What grade is this? I can get the answer of it but I forgot how
Do a gallon man 1G 4Q 2P 2C
Answer:
3.7 hours
Step-by-step explanation:
Pat could do the job alone in 8 hours.
Patti could do the job alone in 7 hours
Output = Rate * time
Let the rate at which pat does the work = Rp
Let the rate at which Patti does the work = Rt
Let X be the total output
Rp * 8 = X
Rp = X/8
Rt * 7 = X
Rt = X/7
If both pat and Patti pick apples, we have
(Rp+Rt)T = X
(X/8 + X/7)T = X
[(7X + 8X)/56]T = X
[X(7+8)/56]T = X
Divide both sides by X
[(7+8)/56]T = 1
(15/56)T = 1
T = 56/15
T = 3.7 hours
