Answer:
After 1.5 second of throwing the ball will reach a maximum height of 44 ft.
Step-by-step explanation:
The height in feet of a ball after t seconds of throwing is given by the function
h = - 16t² + 48t + 8 .......... (1)
Now, condition for maximum height is
{Differentiating equation (1) with respect to t}
⇒ 
seconds.
Now, from equation (1) we get
h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.
Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)
The answer is 2 because it’s -6/3 =2
Answer: Quadrant 2
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Explanation:
Check out the diagram below. An example point in the third quadrant is (-2,-5). This quadrant is the southwest quadrant. Reflect the example point over the x axis (aka the line y = 0) and we get (-2,5). This is shown when we go from point A to point B in the diagram.
The reflection rule is 
showing that only the y coordinate changes from y to -y. If y is negative, then flip to positive, or vice versa. The x coordinate stays the same.
The point started in quadrant 3 and it moves to quadrant 2 after the reflection over the line y = 0.
Side note: all points on the line y = 0 have a y coordinate of 0
Answer:
KL = 9
Step-by-step explanation:
(7 + x - 1)(x - 1) = 12²
(x + 6)(x - 1) = 144
x² -x + 6x - 6 = 144
reduce:
x² + 5x -150 = 0
(x + 15)(x - 10) = 0
x = -15, x = 10
KL = 10 - 1 = 9
The answer is 3x+15 hope this helps :)
