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ANEK [815]
3 years ago
7

Can you solve for y plz

Mathematics
1 answer:
vredina [299]3 years ago
8 0
Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
y = 26/3 or 8 1/3 or 8.333 (those are all the same but in different forms)
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Find 1st, 2nd, 3rd, 4th and 10th nTh term. rule is 3n+4
Irina-Kira [14]

Answer:

When n is 1

3n+4

=3*1+4

=3+4

=7

When n is 2

3n+4

=3*2+4

=6+4

=10

When n is 3

3n+4

=3*3+4

=9+4

=13

When n is 4

3n +4

=3*4+4

=12+4

=16

When n is 10

3n+4

=3*10+4

=30+4

34

7 0
3 years ago
Please help! really needing help solve the problem
guapka [62]

Answer:

7

Step-by-step explanation:

By Basic proportionality theorem:

\frac{10}{8}  =  \frac{3x - 6}{12}  \\  \\  \frac{10 \times 12}{8}  = 3x - 6 \\  \\  \frac{120}{8}  = 3x - 6 \\  \\ 15 = 3x - 6 \\ 15 + 6 = 3x \\ 21 = 3x \\  \frac{21}{3}  = x \\ 7 = x \\  \\  \huge \red { \boxed{x = 7}}

7 0
3 years ago
Please answer this quickly!
kari74 [83]
54/1,000

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7 0
3 years ago
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andreev551 [17]
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3 0
2 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

4 0
3 years ago
Read 2 more answers
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