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ANEK [815]
3 years ago
7

Can you solve for y plz

Mathematics
1 answer:
vredina [299]3 years ago
8 0
Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
y = 26/3 or 8 1/3 or 8.333 (those are all the same but in different forms)
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One cell phone plan costs $29.94 per month plus $.10 for MB of data. Another plan costs $32.99 per month
liubo4ka [24]
Plan 1 = 29.94 + 0.10x
Plan 2 = 32.99 + 0.05x

Plan 1 = Plan 2
29.94 + 0.10x = 32.99 + 0.05x
0.10x - 0.05x = 32.99 - 29.94
0.05x = 3.05
0.05x/0.05 = 3.05/0.05
x = 61

61 MB of data is needed to make both plan equal.

to check: x = 61

29.94 + 0.10(61) = 32.99 + 0.05(61)
29.94 + 6.10 = 32.99 + 3.05
36.04 = 36.04

5 0
4 years ago
Stephen and five of his friends went out to eat. They decided to split the bil
kirill [66]

Hi

Stephen and his five friends = 6 people at the restaurant

Let's call X the amount of the bill.

so if       X/6 = 13.21

              X =  13.21 * 6

               X = 79.26

6 0
3 years ago
Help please I asp !!!
Mice21 [21]

Answer:

Step-by-step explanation:

1

8 0
3 years ago
2. What is the theoretical probability of landing on blue if we have a total of 6 sections? Explain your answer
sashaice [31]

Answer:

1/6 chance

Step-by-step explanation:

3 0
3 years ago
A group of 30 students from your school is part of the audience for a TV game show. The total number of people in the audience i
s344n2d4d5 [400]

Answer:

5.3%

Step-by-step explanation:

The final probability is calculated by means of the quotient of the specific combinations and the total of total combinations

Let's start with the specific ones,

First the number of combinations of 4 of the 30 students getting a spot, i.e .:

A combinations are equal to:

nCx = n! / x! * (n-x)!

Replacing:

30C4 = 30! / (4! * 26!) = 27405

Segundo the number of combinations of the other audience members filling the other 4 (8-4) spots n = 110, 140 - 30

110C4 = 110! / (4! * 106!) = 5773185

Now the total combinations of possible 8 contestants from the audience

140C8 = 140! / (8! * 132!) = 2.98 * 10 ^ 12

Finally, the probability is equal to:

P = (30C4 * 110C4) / 140C8

replacing:

P = 27405 * 5773185 / 2.98 * 10 ^ 12

P = 0.053

Therefore the probability is 5.3%

4 0
4 years ago
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