Polynomials are perfect squares when the first term (term x2) and the third term (term 49) are both squares. In order to find the value of b, you must take the square root of the third term and multiply by the exponent in the first term. This means since the sqrt(49) is 7, and 7x2=14; then the correct answer is C. 14.
-- Remember this only works on perfect square polynomials.
Answer:
B. One solution
Step-by-step explanation:
Here are a system of how two equations can be classified ;
• If the gradients are the same but the y-intercepts are different, the system has no solution.
• If the gradients are different, the system has one solution.
• If the gradients are the same and the y-intercepts are the same, the system has infinitely many solutions.
Y= (x/4) + 3
When x =1
y= 13/4
When x=3
y= 15/4
Gradient of Y= (x/4) + 3
=∆y/∆x
= (15/4 - 13/4)/ ( 3-1)
=( 2/4)÷ 2
=( 2/4 ) × (1/2)
= 1/4
-4x + y = 4
When x= 1
Y= 8
When x=3
Y=16
Gradient of -4x + y = 4
=∆y/∆x
= (16 - 8)/(3-1)= 8/2 = 4
Since the gradients are different then the system has one solution.
Well think of it like this. lets say your teacher made you do this problem -48 - 10. I would just act like 48 is not an negative and add 10. After that I would put the negative back. So the answer would be -58. :P
