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3 years ago

Find the total surface area

Mathematics

1 answer:

Sindrei [870]3 years ago

5 0

Answer:

298 cm^2.

Step-by-step explanation:

There are 3 pairs of faces of equal area.

Area of top = 7 * 11. So it's 2 * 7 * 11 = 154.

Area of a smaller side = 7 * 4 so we have 2*28 = 56 .

Area of larger side = 4*11 so it's 2*44 = 88.

Total surface area = 154 + 56 + 88

= 298.

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3.5 cm = to what ml

zaharov [31]

3.5 cubic centimeters is also equivalent to 3.5 ml

6 0

3 years ago

Find the x-intercept of 2x+2y=2

Nana76 [90]

Answer:

x-intercept: <u>(1,0)</u>

y-intercept: <u>(0,1)</u>

Step-by-step explanation:

Given: Find the x and y intercepts of 2x + 2y = 2

<h2><u>X-intercept</u></h2>

To solve for a x - intercept we have to substitue 0 in for y and solve for $x$

Lets do it:

2x + 2(0) = 2

2x + 0 = 2

2x = 2

x = 1

Therefore, this means that when y = 0, x = 1 or (1,0)

<h2><u>Y-intercept</u></h2>

To solve for a y - intercept we have to substitue 0 in for x and solve for $y$

Lets do it:

2(0) + 2y = 2

0 + 2y = 2

2y = 2

y = 1

Therefore, this means that when x = 0, y = 1 or (0,1)

3 0

2 years ago

the sum of three numbers is 63. The first number is twice the second number, and the third number is three times the first numbe

HACTEHA [7]

Answer:

Step-by-step explanation:

2x+x+3(2x)=63

3x+6x=63

9x=63

9x/9=63/9

X=7

2x=14

3(2x)=42

3 0

3 years ago

Which expression is a quadratic binomial? 3 x 4 −2x x 2 −9x 2 x 4 +9 x 2 −6x−1 7x²

svetlana [45]

To solve the problem shown above it is important to know that a binomial is a polynomial that has two terms. When the highest exponent of the binomial is 2, it is a binomial with degree 2, this is also called or know as "quadratic binomial". Therefore, keeping this on mind, you must identify which of the polynomial above has degree 2.

As you can see, the answer is: <span>−6x−1 7x²</span>

4 0

4 years ago

Find the length of the curve x=e^t e^{-t},\;\;y=5-2t,\;\;0 \le t \le 3.

Oksana_A [137]

$\begin{cases}x(t)=e^t+e^{-t}\\y(t)=5-2t\end{cases}\implies\begin{cases}x'(t)=e^t-e^{-t}\\y'(t)=-2\end{cases}$

The length of the curve is given by the integral

$\displaystyle\int_0^3\sqrt{(e^t-e^{-t})^2+(-2)^2}\,\mathrm dt$

Expand and rewrite the integrand:

$(e^t-e^{-t})^2+(-2)^2=e^{2t}+2+e^{-2t}$
$=e^{-2t}(e^{4t}+2e^{2t}+1)$
$=e^{-2t}(e^{2t}+1)^2$
$\implies\sqrt{(e^t-e^{-t})^2+(-2)^2}=\dfrac{e^{2t}+1}{e^t}$

Now the integral is

$\displaystyle\int_0^3\dfrac{e^{2t}+1}{e^t}\,\mathrm dt=\int_0^3(e^t+e^{-t})\,\mathrm dt$
$=2\displaystyle\int_0^3\cosh t\,\mathrm dt$
$=2\sinh t\bigg|_{t=0}^{t=3}$
$=2\sinh 3$

7 0

3 years ago