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2 years ago

Consider the numbers 4 and √5. Which operation(s) will result in an irrational number?

Mathematics

1 answer:

tekilochka [14]2 years ago

5 0

Answer: D (both the sum and the product).

Step-by-step explanation:

Let's add: 4 + sqrt5 will still seem irrational.

Let's multiply: 4*sqrt5 = 4sqrt5, which is irrational.

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(True or False) The set of ordered pairs {(6,4),(2,-5),(-2,4),(6,-4)} is a function

const2013 [10]

Answer:

False

Step-by-step explanation:

The same function input (the first number in the pair) cannot have two different outputs (the second number in the pair).

(6, 4) 4 is one output.

(6, -4) -4 is another output.

6 0

3 years ago

Which is greater <br><br>515_5.05

Elis [28]

Answer:

515

Step-by-step explanation:

it's self-explanatory

7 0

3 years ago

Read 2 more answers

If three times a number decreased by 10 is 25, what is the number

mafiozo [28]

Let the number be n
3*n - 10=25
3*n=25+10
3*n=35
n=35/3=11*2/3=11.67

4 0

3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

50 points! Answer AS much as you can, I give Brainliest!

olga_2 [115]

Answer:

9. y = 8

10. n = 21

11. 44 = v

12. c = 35

Step-by-step explanation:

9. 9y = 72

Divide each side by 9

9y/9 = 72/9

y = 8

10. 3n = 63

Divide each side by 3

3n/3 = 63/3

n = 21

11. 4 = v/11

Multiply each side by 11

4*11 = v/11*11

44 = v

12. c/7 = 5

Multiply each side by 7

c/7*7 = 5*7

c = 35

8 0

3 years ago

Read 2 more answers