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3 years ago

13

Can the remainder in a division problem ever equal the divisor? explain why or why not.

2 answers:

mash [69]3 years ago

6 0

Lets imagine we have 8/2. We all know the answer is 4, because if i have 8 objects and i want to divide them equally amond 2 ppl, each will get 4 objects. However, if the remainder would equal the divisor, one would say 8/2= 4 remainder 4. This means that one person succesfully got the 8 objects, and there are 4 left. But each person needs 4 objects, so the remaining objects can fully satisfy mathematical inductive perpectives, so the person may take the full 4 objects

erastovalidia [21]3 years ago

5 0

No, cause the remainder might be bigger than divisor.

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Step-by-step explanation:

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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natka813 [3]

Answer:

Option A

Step-by-step explanation:

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Since, cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$ = $-\frac{2\sqrt{5} }{5}$

= $\frac{2}{\sqrt{5}}$

By applying Pythagoras theorem in the right triangle,

(Hypotenuse)² = (Opposite side)² + (Adjacent side)²

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Opposite side = √(5 - 4)

= 1

Since, sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{1}{\sqrt{5}}$

Since, sine is positive in IInd quadrant,

sinθ = $\frac{1}{\sqrt{5}}$

Therefore, option A will be the answer.

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Step-by-step explanation:

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