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2 years ago

Given the following graph what is the slope?

Mathematics

1 answer:

balandron [24]2 years ago

3 0

Answer:

slope = $\frac{1}{4}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 1) and (x₂, y₂ ) = (0, 2) ← 2 points on the line

m = $\frac{2-1}{0-(-4)}$ = $\frac{1}{0+4}$ = $\frac{1}{4}$

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Fifteen more than twice a number is 9

Elden [556K]

2x+15=9
2x= -6
so the answer is -3

7 0

3 years ago

Find the coordinates of k

marin [14]

If you plot the coordinates on a piece of graph paper your answer would come out too (1,-8)

4 0

3 years ago

Please help! thanks :)

Molodets [167]

Answer:

118%

Step-by-step explanation:

Cora's kitten weighed in the last visit to the veterinarian's office= 550 grams

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7 0

3 years ago

2.50c+6a=6344.50 <br> Find each variable

Ksju [112]

Answer:

c=2.4a+2537.8

a=-2.5/6c+1057.4

Step-by-step explanation:

solve for c:

2.50c+6a=6344.50

-6a -6a

2.50c=-6a+6344.50

/2.50 /2.50 /2.50

c=2.4a+2537.8

solve for a:

2.50c+6a=6344.50

-2.5c -2.5c

6a=-2.5c+6344.50

/6 /6 /6

a=-2.5/6c+1057.4

6 0

3 years ago

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

3 0

3 years ago