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Digiron [165]
3 years ago
6

What is the value of x in the equation 1,331x3 − 216 = 0?

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0
3777 is the correct answer
algol [13]3 years ago
4 0
In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.
Hope yhis helps
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A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.41 mpa and a sample standa
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For this problem, the confidence interval is the one we are looking for. Since the confidence level is not given, we assume that it is 95%.

 

The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n


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<span>
</span>

α= 5%


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t 0.025, 19 = 2.093 (check t table)


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So plugging in our values:


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Read 2 more answers
Can somebody help, will give brainliest
grigory [225]

9514 1404 393

Answer:

  • c = 2
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The sum of top and bottom bases is twice the midsegment.

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The value of c is 2; the segment lengths (top-down) are 10, 8, 6.

5 0
2 years ago
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