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marin [14]
3 years ago
11

What is the midpoint of a line segment with the endpoints (-4, -3) and (7, -5)

Mathematics
2 answers:
masya89 [10]3 years ago
6 0

Answer:

(1.5,-4)

quick and easy

Katyanochek1 [597]3 years ago
4 0
Midpoint Formula: (\frac{x+x}{2},\frac{y+y}{2})
Midpoint = (\frac {-4+7}{2},\frac {-3-5}{2})
Midpoint = (\frac {3}{2},\frac {-8}{2})
Midpoint = (\frac {3}{2}, -4)
So, the midpoint of the endpoints (-4,-3) and (7,-5) is (\frac {3}{2}, -4).
Have a nice day! ♪
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so [3,5)

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Evaluate 3-8/2 +3x5​
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it costs $2.48 for a 16 ounce jar of peanut butter and $5.44 for a 40 ounce jar. which jar is the better buy
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2 years ago
Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability
krok68 [10]

Answer:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

So for this case we can solve for P(A) like this:

P(A) = 1-P(A') = 1-\frac{68}{73}=\frac{5}{73}

And now we can find P(A \cup B) using the total probability rul given by:

P(A \cup B) = P(A)+P(B) -P(A \cap B)

And if we replace the values given we got:

P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}

And that would be the final answer.

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<h3>How to find the equivalent form of a proposition</h3>

Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x))

To learn more on propositions: brainly.com/question/14789062

#SPJ1

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