The range of the given relation is D. R = {-1, 3, 5, 8}.
Step-by-step explanation:
Step 1:
The range of a relation is the second set of values while the domain constitutes the first set of values.
There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.
Step 2:
The range of (1, -1) = -1,
The range of (2, 3) = 3,
The range of (3, 5) = 5,
The range of (4, 8) = 8.
Combining these values we get the range as {-1, 3, 5, 8} which is option D.
Answer:
86
Step-by-step explanation:
<u>Perimeter of WXY = WSY+WRX+XY</u>
<em>--> WSY = SY x 2</em>
--> WSY = 16 x 2 = 32
<em>Since it is an isosceles triangle, WRX = WSY</em>
--> WRX = 32
<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>
<em>--> Solve it using the cos theta rule</em>
--> Angle = Angle X = 70°
Hypotenuse = WRX = 32
Adjacent = WA = ?
<em>--> Cos (Angle) = Adjacent/Hypotenuse</em>
Cos (70) = WA/32
WA = 10.9 rounded off to 11
--> WA=AY= 11
--> XY = WA + AY = 11+11 = 22
<em>--> Perimeter = WSY+WRX+XY</em>
Perimeter = 32+32+22
Perimeter = 86
Therefore, the perimeter of WXY is 86.
Slope= (Y2-Y1)/(X2-X1)
Slope=(3-(-4) ) /(-14-(-7) )
Slope= (3+4)/(-14+7)
Slope=7/-7
Slope= -1
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
