Answer and Step-by-step explanation:
We know that t is in minutes, and 1 hours is equal to 60 minutes, so we plug in 60 for t.
C = 0.25(60) + 3.50
C = 15 + 3.50
C = 18.50
<em><u>The cost to rent the canoe is $18.50.</u></em>
<em><u></u></em>
<em><u></u></em>
<em><u></u></em>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
5.815 equals to 5815\1000
Answer:
(0,2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Solution by completing the square for:
x2−12x+9=0
Keep x terms on the left and move
the constant to the right side
by subtracting it on both sides
x2−12x=−9
Take half of the x term and square it
[−12⋅1/2]^2=36
then add the result to both sides
x^2−12x+36=−9+36
Rewrite the perfect square on the left
(x−6)^2=−9+36
and combine terms on the right
(x−6)^2=27
Take the square root of both sides
x−6=±27−−√
Simplify the Radical term (1):
x−6=±3–√3
Isolate the x on the left side and
solve for x (1)
x=6±3–√3
therefore (2)
x=6+3–√3
x=6−3–√3
which becomes
x=11.1962
x=0.803848
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
-----------
Example:
f(x) = x^3 - 29
This function has one real-number root of ![x = \sqrt[3]{29}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B29%7D)
(cube root of 29) and the other two roots are complex or imaginary roots.
