![\displaystyle\lim_{n\to\infty}\sqrt[n]{\left|\left(\frac{5n+15}{2n-1}\right)^n\right|}=\lim_{n\to\infty}\frac{5n+15}{2n-1}=\dfrac52](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bn%5Cto%5Cinfty%7D%5Csqrt%5Bn%5D%7B%5Cleft%7C%5Cleft%28%5Cfrac%7B5n%2B15%7D%7B2n-1%7D%5Cright%29%5En%5Cright%7C%7D%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cfrac%7B5n%2B15%7D%7B2n-1%7D%3D%5Cdfrac52)
Since this limit exceeds 1, the series diverges.
You would solve it in two parts.
4*n = 44 Divide by 4
4n/4 = 44/4
n = 11
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z^m * z^2 = z^9
When the bases are the same (on the left) the powers on the left add
m + 2
The powers on the left side of the equation are the same as the powers on the right when the bases are the same.
m + 2 = 9 Subtract 2 from both sides.
m + 2 - 2 = 9 - 2
m = 7
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Answers
m = 7
n = 11
set up an equation for this. x will be the score of the losing team. x+2x=96. Then solve for x. 3x=96. x=96/3 x=32. So the losing team got 32 points and the winning team got 64
Answer:
36 &49
Step-by-step explanation:
6²=36
7²=49
