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Keith_Richards [23]
3 years ago
6

Plz help fast i need hlp

Mathematics
2 answers:
julsineya [31]3 years ago
8 0
A=b*h
area = 7*4.2
area = 29.4
astra-53 [7]3 years ago
4 0

Answer:

idk  

Step-by-step explanation:

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Please help me with this question! thank you :)
nikdorinn [45]

Answer:

2 + 2 = 0

Step-by-step explanation:

It's easy you are

kid‍♂️‍♂️‍♂️

3 0
2 years ago
3 over the whole value of (x2−5x+6) = a over the whole value of (x−2) + b over the whole value of (x−3)
muminat
I guess that's all you can do
to find a and b you need more information

b=-a -> a (x-3)-a (x-2)=3
a [x-3-(x-2)]=3
a (x-3-x+2)=3
a*(-1)=3
a=3:(-1)
a=-3
b=-a=-(-3)=3

5 0
2 years ago
Help!! Thank you so much!!
Orlov [11]

The volume we're looking for is the volume of both cones in the figure.

The volume of a cone is  V=\pi r^2\frac{h}{3} .

So, V_{tot} = V_{1} + V_2 .

<u>Cone 1's variables:</u>

r = 2.6

h = 5

<u>Cone 2's variables:</u>

r = 2.6

h = 3

Now we can just plug and chug!

V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68

V = c. 56.6 cubic units

5 0
2 years ago
How are percents related to rates?
BartSMP [9]

Answer:

A percentage is defined as the ratio of two numbers times 100.

3 0
2 years ago
Read 2 more answers
Write the equation of the parabola in vertex form. <br> vertex (2,1) point (3,-3)
Mariana [72]

first off let's notice that hmmm the vertex is above the point (3,-3), so if we "assume" is a vertical parabola, then it'd be opening downwards.... anyhow that said, let's plug in those values.

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf vertex~~(\stackrel{h}{2}~~,~~\stackrel{k}{1})\qquad \implies \qquad y = a(x-2)^2+1 \\\\\\ \stackrel{\textit{we also know that }}{(3~~,~~-3)} \begin{cases} x = 3\\ y = -3 \end{cases}\qquad \implies -3=a(3-2)^2+1 \\\\\\ -3=a(1)^2+1\implies -3=a+1\implies -4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = -4(x-2)^2+1~\hfill

6 0
3 years ago
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