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2 years ago

How do you do that?????

Mathematics

1 answer:

Elden [556K]2 years ago

5 0

This question is easy once you understand. So when adding, subtracting, multiplying, or dividing with whole numbers you turn it into a fraction. So 12 is going to become 12/1. 8 1/8 is a mixed number so we have to turn it into an incomplete fraction. Here is how you do it. Multiply the denominator by the who number. So 8 x 8 = 64. Then you add your product to the numerator, which will make it 65. Then after this you keep your denominator giving you 65/8. Now we have to find the common denominator by finding the LCM. So the LCM is 8. Next we divide the old denominator by the new denominator. So 1 goes into 8, 8 times. And next 8 x the numerator. so 8 x 12 = 96. We do the same to the other side. Now we have 96/8 - 65/8 = 31/8. Finally we make this a mixed number. So 31 divided by 8. So you should get 3 7/8.

I hope this helps! :)

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3 years ago

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2 years ago

A college library has five copies of a certain text on reserve. Two copies (1 and 2) are first printings, and the other three (3

sleet_krkn [62]

Answer:

B) Outcomes in A = {3, 4, 5} .

C) Outcomes in B = {5, 15, 25, 125, 215} .

D) Outcomes in C = {3, 4, 5, 23, 24, 25} .

Step-by-step explanation:

We are given that a college library has five copies of a certain text on reserve. From which two copies (1 and 2) are of first printings, and the other three (3, 4, and 5) are of second printings.

Also, it is stated that a student will stop examining the books only when a second printing has been selected.

A) The outcomes in S are :

 Number of outcomes Selection of Outcomes

1 3

2 4

3 5

4 13

5 14

6 15

7 23

8 24

9 25

10 123

11 124

12 125

13 213

14 214

15 215

Here outcome 123 means 1st copy of first printing is examined then 2nd copy of first printing is examined and then 3rd copy of second printing is examined and then the student stops.

B) A denote the event that exactly one book must be examined.

So, the outcomes in A will be outcome number 1, 2 and 3 corresponding to selection 3, 4 and 5 of second printing because in these outcomes only one book is examined.

Hence, outcomes in A = {3, 4, 5} .

C) B be the event that book 5 is the one selected. It means all those outcomes in which book 5 was last examined. So, the outcomes in B will be outcome number 3, 6, 9, 12, 15 corresponding to selection 5, 15, 25, 125, 215

Hence, outcomes in B = {5, 15, 25, 125, 215} .

D) C be the event that book 1 is not examined which is outcome number 1, 2, 3, 7, 8, 9 corresponding to selection 3, 4, 5, 23, 24, 25 .

Hence, outcomes in C = {3, 4, 5, 23, 24, 25} .

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3 years ago

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Answer:

(1, 3)

Step-by-step explanation:

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2 years ago