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3 years ago

Write the equation of a line that is perpendicular to

Mathematics

1 answer:

DIA [1.3K]3 years ago

5 0

Answer:

i would help but im not smart enough sorry

Step-by-step explanation:

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Please Explain!!<br> I need help plss

Nimfa-mama [501]

Answer:

See step by step

Step-by-step explanation:

For A. use any two factors that multiply to 100 that isn't 25 and 4.

For b Use one obtuse angle (angle over 90 degree) and two acute angles. Make sure they add up to 180.

For c Use any two values that add up to 52 since they didnt establish y as the midpoint.

For d. measure of angle 1 is 45 and measure of angle 2 is 45 degrees

6 0

3 years ago

Read 2 more answers

2/5(d−10)−2/3(d+6) is

MissTica

Remove parentheses
2/5 • d-10 - 2/3 • d+6

calculate
2/5d-4 - 2/3d-4

the answer
-4/15d-8

3 0

3 years ago

The length of each side of a square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of ea

densk [106]

Check the picture below.

6 0

3 years ago

What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?

kvasek [131]

Answer:

The center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

here,

r = raduis

center = (a, b)

Given the equation

$\left(x-14\right)^2+\left(y+21\right)^2=64$

$\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2$

comparing with the circle equation

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

Therefore, the center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

7 0

3 years ago

A medication is available in 1000mcg per mL.<br><br> How much is needed for a 0.8mg dose?

Setler [38]

Answer:

5 doses of medication and 1000ml

8 0

2 years ago