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jekas [21]
3 years ago
8

Please answer seriously thanks !! will give brainliest

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

Step-by-step explanation:

21) CD -  chord   (segment)

22)FG - line

23) EC  - segment -  diameter

24) AB - segment - radius

25) H - Point

26) A - Point

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How to represent y=4x+50 on a graph
adelina 88 [10]
You're going to go to 50 on the y-axis and put a point there and then from 50 the slope needs to be a rise over run so go up 4 right 1:)
5 0
3 years ago
How can this same solution be written using set builder notation? {x | x > }?
skad [1K]

<u>Corrected Question</u>

The solution to an inequality is represented by the number line. How can this same solution be written using set-builder notation? {x | x > }

Answer:

\{x | x >3 \}

Step-by-step explanation:

Given an inequality whose solution is represented by the number line attached below.

We observe the following from the number line

There is an open circle at 3, therefore the solution set does not include 3. (We make use of > or < in cases like that)

The arrow is pointed towards the right. All points to the right of 3 are greater than 3, therefore:

The solution in the number line can be written using set-builder notation as:

\{x | x >3 \}

5 0
4 years ago
Please help me figure this out it’s due on 15 minutes
Olin [163]

Answer:

Step-by-step explanation:

1. area of square=10²=100 cm²

area of circle=πr²=π×2.5²=6.25π cm²

reqd. area=100-6.25π ≈80.375 cm²

2.

area of circle=π×2.5²=6.25π≈6.25×3.14≈19.625 cm²

area of rectangle=4×3=12 cm²

reqd. area=19.625-12≈7.625 cm²

3.

area of two circles=2×π×3²=18π≈18×3.14≈56.52 cm²

area of square=12²=144 cm²

reqd. area=144-56.52≈87.48 cm²

4.

area of smaller circle=π×4²=16π cm²

area of bigger circle=π×8²=64π cm²

area of two circles=16π+64π=80π cm²

diameter of bigger circle=4+4+8+8=24 cm

diameter of biggest circle=π×12²=144π

area of shaded region=144π-80π=64π≈200.96 cm²

5 0
3 years ago
On a school trip, a class travels 52.6 kilometers by train and 4.136 kilometers by bus. How far did the class travel? pls help
levacccp [35]

Answer:

56.736kilometers

Step by step explanation:

52.6

+<u> </u><u>4.</u><u> </u><u>136</u><u> </u>

<u>56.736</u><u> </u>

=56.736 kilometers

7 0
3 years ago
If DE=52 and EF=21, find DE
dalvyx [7]

Answer:

52

Step-by-step explanation:

You already said that DE=52.

5 0
3 years ago
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