Answer:
<h2>

</h2>
Option B is the correct option.
Step-by-step explanation:

Move constant to R.H.S and change its sign:

Take the L.C.M


Calculate

Hope this helps...
Good luck on your assignment..
Answer:
man that's hard I'm still in class 6
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
49=-7k is equivalent to D because when you simplify both of them, you get -7=k
Answer:
65.62
Step-by-step explanation:
Given:
After eating a meal at a restaurant, we decided to tip 25%, building a grand total of $87.50.
To find:
Price before tip
Solution:
87.50 × 25% = 21.875
~Round~: 21.875 to 21.88
87.50 - 21 .88 = 65.62
Thus the price before the tip is 65.62
Check Answer:
<em>Formula: Higher number - Lower number ÷ original number × 100</em>
<em>Solve: </em>
<em>87.50 - 65.62 = 21.88</em>
<em>21.88 ÷ 87.50=0.25005714285</em>
<em>0.25005714285 × 100 = 25.0057142857</em>
<em>Round - 25%</em>
<u><em>~lenvy~</em></u>