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Anna11 [10]
3 years ago
5

Find the square root of 256 an cube root of 729​

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

i)16

ii)9

Step-by-step explanation:

\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9

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Please help me with this pleaseee
torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = \frac{opposite}{adjacent} = \frac{500}{x}

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = \frac{500}{tan80} ≈ 88.2

5 0
3 years ago
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AlladinOne [14]
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Which of the following vectors are orthogonal to (1,5)? Check all that apply
Andre45 [30]
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal

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</span><span>B. (10,-2)
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<span>C. (-1,-5)
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<span>D. (-5,1)
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the answer is 
B. (10,-2) and D. (-5,1)  are  orthogonal  to  (1,5)
7 0
3 years ago
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sergejj [24]

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Find q. Write your answer in simplest radical form.
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Answer:

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Step-by-step explanation:

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