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laila [671]
3 years ago
6

Pleaseeeee help with all these pics

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

pic 1 left side 3.35, Pic 1 Right side .75

Pic 2 2934

Step-by-step explanation:

Pic 1 Left side:

1.5+2.25=3.75

Pic 1 Right side

2.25-1.5=.75

Pic 2

978*3=2934

Bumek [7]3 years ago
4 0

Answer:

1. 0.75

2. 2934

Step-by-step explanation:

1. Just subtract the larger number from the smaller one.

2. Multiply the two numbers together.

You might be interested in
What is the smallest integer $n$ such that $5n + 3 > -10$?
Nataliya [291]

Answer:

-2

Step-by-step explanation:

5n+3= -10

5n = -13

n = -13/5

= -2.6

question is integer

so answer is -2

8 0
3 years ago
Solve for x. Round to the nearest tenth of a degree, if necessary.​
MissTica

Answer:

x ≈ 54.8°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{PQ}{QR} = \frac{7.1}{5} , then

x = tan^{-1} (\frac{7.1}{5} ) ≈ 54.8° ( to the nearest tenth )

4 0
2 years ago
Please help me with these 2 question.
maks197457 [2]

Answer:

Step-by-step explanation:

- sqrt(39) and square root 47

are the limits. The - square root of 39 is smaller than - 6. So the integer to use here is - 6

sqrt (47) = 6.686. Here the square root is larger than the closest integer.

The integer to use is 6

- 6 + 6 = 0

4 0
2 years ago
Prove that the product of the second and third numbers out of four consecutive whole numbers is two greater than the product of
podryga [215]

Let the four consecutive numbers be x,x+1,x+2,x+3.

Now the product of second and third number=(x+1)(x+2)=x²+3x+2=k

Product of first and fourth number=x(x+3)=x²+3x=k-2

A.T.Q

product of second and third number= product of first and fourth number+2

Hence proved

6 0
3 years ago
Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.​
trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

A=P\left (1+\dfrac{r}{n}\right)^{nt}

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}

A=2000\left (1.05\right)^{4}

A=2000\left (1.21550625\right)

A=2431.0125

Now, the compound interest is

C.I.=A-P

C.I.=2431.0125-2000

C.I.=431.0125

Therefore, the compound interest is Rs 431.0125.

3 0
3 years ago
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