X² = 1/4 ⇒√⇒ x₁ = 1/2, x₂ = -1/2
Π=180⁰
-7π/2=(-7*180)/2=-7*90=-630⁰
-7π/2= -630⁰
<span>93 * 10^9 = 9.3 * 10^10
</span>
<span>Line ET is tangent to circle A at T
</span>
∴ ET ⊥ TN
∴ ∠ ETN = 90
<span>the measure of Arc TG = 70
</span>
∠ TNG = half <span>the measure of Arc TG = 0.5 *70 = 35
</span>
<span>Δ ETN ⇒ The sum of all angles = 180
</span>
<span>∴∠ GET = ∠ NET = 180 - (90 + 35 ) = 55
</span>
∴ The correct answer is option <span>A. 55°</span>
The given problem is :
(6x^4 + 15x^3 − 2x^2 + 10x − 4) ÷ (3x^2 + 2)?
now we can write expression (6x^4 + 15x^3 − 2x^2 + 10x − 4) as
(6x^4 + 4x^2 + 15x^3 + 10x - 6x^2 -4)
we have somehow arrange the expression in a way that 3x^2 + 2 is common
now the expression comes out to be
2x^2(3x^2 + 2) + 5x(3x^2+2) -2(3x + 2) / (3x^2+2)
After dividing final result comes out to be (2x^2 + 5x -2)