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Andreas93 [3]
3 years ago
11

What is the expression in radical form? (3x^2)^2/3

Mathematics
2 answers:
wariber [46]3 years ago
4 0

Answer:

The required radical form is \sqrt[3]{9x^4}.

Step-by-step explanation:

Consider the provided expression.

(3x^2)^\frac{2}{3}

The above expression can be written as:

\sqrt[3]{(3x^2)^2}

Now use the property of exponent:

(a^m)^n=a^{(m\times n)}=a^{mn}

Use the above property as shown:

\sqrt[3]{3^2x^{2\times 2}}

\sqrt[3]{9x^4}

Hence, the required radical form is \sqrt[3]{9x^4}.

Ket [755]3 years ago
3 0
I hope this helps you

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Step-by-step explanation:

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Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral
Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every a\in A then (a,a)\in R.

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if (a,b)\in R then (b,a)\in R for all a,b\in A.

So, the relation R is a symmetric relation because if a line l_1 is parallel to the line l_2 the always the line l_2 is parallel to the line l_1.

A relation R on a set A is called transitive relation if (a,b)\in R and (b,c)\in R then (a,c)\in R for all a,b,c\in A.

So, the relation R is a transitive relation because if a line l_1 s parallel to the line l_2 and the line l_2 is parallel to the line l_3 then the always line l_1 is parallel to the line l_3.

Therefore the relation R is a reflexive, symmetric and transitive relation.

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3 years ago
How do I simplify negative square root of 72
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Solve for positive 72 and separate the negative part as \sqrt{-1} The rest of calculation is same..
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