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Andreas93 [3]
3 years ago
11

What is the expression in radical form? (3x^2)^2/3

Mathematics
2 answers:
wariber [46]3 years ago
4 0

Answer:

The required radical form is \sqrt[3]{9x^4}.

Step-by-step explanation:

Consider the provided expression.

(3x^2)^\frac{2}{3}

The above expression can be written as:

\sqrt[3]{(3x^2)^2}

Now use the property of exponent:

(a^m)^n=a^{(m\times n)}=a^{mn}

Use the above property as shown:

\sqrt[3]{3^2x^{2\times 2}}

\sqrt[3]{9x^4}

Hence, the required radical form is \sqrt[3]{9x^4}.

Ket [755]3 years ago
3 0
I hope this helps you

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If the cost of a 2.5 meter cloth is $30.5. What will be the cost of 22 meters ?
alisha [4.7K]

Answer:

268.40

Step-by-step explanation:

We can write a ratio to solve

2.5 meters        22 meters

-----------------  = --------------

30.5 dollars       x dollars

Using cross products

2.5 * x = 30.5 * 22

2.5x =671

Divide each side by 2.5

2.5x / 2.5 = 671/2.5

x =268.4

8 0
3 years ago
3. *
Sati [7]

Answer:

A first numbers cant be same

5 0
2 years ago
Helpppppp mathhh failing
LenKa [72]
Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2  = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5

sin30 = b/a
1/2 = 5√3  / a

a = 5√3 (2)
a = 10√3

c^2 = (10√3)^2  -  (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15

so
a =10√3,  b = 5√3, c = 15,d = 5
answer is
D. last choice

4 0
3 years ago
Dion went out to lunch. The bill, including tax, was $30. Dion left a tip of $6. What percent of the bill did Dion leave as tip?
Annette [7]
Sorry about my first answer then it would 20% because if you take 30 and divide 20% you'll get 6 so again sorry I was wrong 20 percent though is right.
4 0
3 years ago
Lifetime of $1 Bills The average lifetime of circulated $1 bills is 18 months. A researcher believes that the average lifetime i
OLEGan [10]
<h2>Answer with explanation:</h2>

Let \mu be the population mean lifetime of circulated $1 bills.

By considering the given information , we have :-

H_0:\mu=18\\\\H_a:\mu\neq18

Since the alternative hypotheses is two tailed so the test is a two tailed test.

We assume that the lifetime of circulated $1 bills is normally distributed.

Given : Sample size :  n=50 , which is greater than 30 .

It means the sample is large so we use z-test.

Sample mean : \overline{x}=18.8

Standard deviation : \sigma=2.8

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{18.8-18}{\dfrac{2.8}{\sqrt{50}}}\approx2.02

The p-value= 2P(z>2.02)=0.0433834

Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.

6 0
3 years ago
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