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2 years ago

Seven tickets for a Broadway show cost $385. How much will only 4 tickets cost?

Mathematics

2 answers:

jeka942 years ago

7 0

Answer:

$220

Step-by-step explanation:

If seven tickets cost 385, then 1 ticket costs one-seventh of that amount, so we divide it by 7 to see how much one ticket costs.

385/7 = 55

One ticket is $55. To find out how much 4 tickets cost, multiply 55, the price of one ticket, by 4.

55 * 4 = 220

$ tickets cost $220

irina1246 [14]2 years ago

6 0

Answer:

That seems a little hard-

Step-by-step explanation:

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The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago

F(x) = x2 + 1 g(x) = 5 – x (f – g)(x) =

Blizzard [7]

Answer:

x^2+x-4

Step-by-step explanation:

(f-g)=(x^2+1)-(5-x)

=x^2+1-5+x

=x^2+x-4

4 0

3 years ago

What is the inverse of y=x+5

V125BC [204]

Answer:

x=-5

Step-by-step explanation:

4 0

3 years ago

Which of the following expressions is equivalent to -2-5?

Vanyuwa [196]

-7 Hope this helps. :)

6 0

3 years ago

Read 2 more answers

Cynthia Besch wants to buy a rug for a room that is 1919 ft wide and 2727 ft long. She wants to leave a uniform strip of floor a

yulyashka [42]

Answer:

The dimension of the rug would be 17 ft × 9 ft.

Step-by-step explanation:

Given

length of the room = 27 ft.

width of the room = 19 ft.

suppose, she leaves a uniform strip of x ft. around the rug.

So,

The length of rug = (27-2x)ft.

Width of rug= (19-2x)ft.

∴ Area of the rug= length×width

$= (27-2x)(19-2x)$

$= 513-54x-38x+4x^2$

$= 513-92x+4x^2$

According to the question,

$513-92x+4x^2=153$

$513-92x+4x^2-153=0$ ( subtract 153 both sides)

$4x^2-92x+360=0$

$4(x^2-23x+90)=0$

$x^2-23x+90=0$

$x^2-(18+5)x+90=0$ ( Middle term splitting)

$x^2-18x-5x+90=0$

$x(x-18)-5(x-18)=0$

$(x-5)(x-18)=0$

$x-5=0$ or $x-18=0$ ( zero product property)

$x=5$ or $x=18$

if x=18, dimension would be negative ( Not possible)

Thus, x= 5

Hence,

length of rug= 27-10=17 ft.

width of rug= 19-10=9 ft.

8 0

3 years ago