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DENIUS [597]
4 years ago
7

I'll make you the branliest if you answer this question correctly

Mathematics
2 answers:
denis-greek [22]4 years ago
4 0

Every hour, the number of liters decreases by 0.5 liter.

Anettt [7]4 years ago
3 0

It takes 0.5 hour for the water to decrease by one liter. You can also tell because the line is going down showing that it is decreasing or you can subtract the X-axis

2 - 1.5 which equals 0.5.

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In California, we need more rain to sustain the health of our natural environment, argriculture, and
astra-53 [7]

Answer:

In California, we need more rain to sustain the health of our natural environment, argriculture, and economic. A group of statistics students in Oxnard College recorded the amount of rain during 2016-2017 school year, measuring the intensity by the inches of rain, and the results were:

Inches of Rain 1 2 3 4 5 6

Frequency 2 4 3 3 7 3

The mean (¯xx¯) rain intensity: ____ inches (Please show your answer to 1 decimal place.)

The median rain intensity: __3.8__ inches

Step-by-step explanation:

the answer is 3.8

4 0
3 years ago
Ron and Ben had a total of 700 playing cards. After Ron gave away 40% of his playing cards and Ben gave away 20% of his playing
allsm [11]
Ron had 140 picture cards more than Ben
5 0
3 years ago
A scale drawing of an American flag is 10 inches and 6 inches tall the actual flag is 3 feet tall. What is the area of the actua
Natali [406]
15 square feet because the scale is 2 in:1 ft so it would be 10/2 which is 5. This means the flag is 5 ft x 3 ft aka 15 square feet
6 0
3 years ago
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf
kobusy [5.1K]

Answer:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We have the following data given:

\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by \alpha=1-0.93=0.07 and \alpha/2 =0.035. And the critical value would be given by:  

z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811  

The confidence interval is given by:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

4 0
3 years ago
Set up the integral that would give the volume v generated by rotating the region bounded by the given curves about the y-axis.
lorasvet [3.4K]
Consider, pls, this solution.
Note, that V1 marked with orange lines (see the graph), V2 - with green colour.

6 0
3 years ago
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