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Gnesinka [82]
3 years ago
11

Ok so I now fix it, can you help me?

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

1 80%

2 80%

3 80%

Step-by-step explanation:

Zinaida [17]3 years ago
4 0

Answer:

1st Question is: 80%

2nd Question is: Option 'D'

Step-by-step explanation:

Both make a matter of 80%, the first one is because 4/5 in radical form is 80/100, The second answer is because 462 + 378 = 840, 840 simplified with 1,050 makes 4/5 = 80/100 or 80%

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Find the range median first and third interquartile range for each data set
liraira [26]

Answer:

Range = 1.8

Median = 6.3

First Quartile = 6.3

Thrid Quartile = 6.8

Interquartile Range =  0.5

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4.9, 5.8, 6.1, 6.2, 6.3, 6.3, 6.4, 6.6, 6.7, 6.7

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 6.7 - 4.9

Range = 1.8

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 6.3 + 6.3 /2

Median = 6.3

To get the first quartile, we simply get the median of the lower of the data set.

4.9, 5.8, 6.1, 6.2, 6.3

The median of the first quartile is 6.1.

To get the third quartile, we get the median of the upper half of the data set.

6.3, 6.4, 6.6, 6.7, 6.7

The median of the third quartile is 6.6

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 6.6 - 6.1

Interquartile Range = 0.5

Answer:

Range = 32

Median = 17.5

First Quartile = 15

Thrid Quartile = 19

Interquartile Range =  4

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4, 9, 15, 16, 17, 18, 18, 19, 19, 36

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 36 - 4

Range = 32

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 17 + 18 /2

Median = 17.5

To get the first quartile, we simply get the median of the lower of the data set.

4, 9, 15, 16, 17,

The median of the first quartile is 15.

To get the third quartile, we get the median of the upper half of the data set.

18, 18, 19, 19, 36

The median of the third quartile is 19.

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 19 - 15

Interquartile Range = 4

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1)

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