1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zvonat [6]
3 years ago
12

Mr. Baker gave his English class a chance to earn extra points for the quarter by conducting research about a famous author. He

gave them points based on how many hours they spent in the library researching their author. Seven students participated in the assignment, and their extra-credit points are shown here. What is the median of their extra credit points?
Mathematics
2 answers:
KIM [24]3 years ago
7 0
May I have answers to choose from.

gregori [183]3 years ago
4 0

Answer:

the answer is 10


Step-by-step explanation:


You might be interested in
In 2010, the population of Kingsford was 8000. By 2014 the population had increased by 15% and 2/5 of the population was age 12
Anastasy [175]
<h2>Hello!</h2>

The answer is: The population age 12 or under was 3680.

<h2>Why?</h2>

If in 2010 the population of Kignsford was 8000, and by 2014 the population had increased by 15% we need to calculate the total population and then, calculate how many people was age 12 or under.

We must remember that we cannot work with percentage values, so, to make 15% a real number, we need to divide it by 100:

15(Percentage)=\frac{15}{100}=0.15

So,

Calculating the population by 2014, we have:

Population_{2014}=Population_{2010}+ Population_{2010}*0.15

Then, substituting we have:

Population_{2014}=8000+ 8000*0.15=9200

Now, calculating the population that was age 12 or under, knowing that it was 2/5 of the total population, we have:

Population=TotalPopulation*\frac{2}{5}\\\\Population=9200*\frac{2}{5}=3680

So, the population age 12 or under was 3680.

Have a nice day!

6 0
3 years ago
Evaluate 3z + 2[z-1) when z = 5
Gnesinka [82]

Answer:

23

Step-by-step explanation:

3z + 2(z-1)

Let z=5

3*5 +2( 5-1)

15 +2(4)

15+8

23

7 0
3 years ago
How many whole numbers are there, whose squares and cubes have the same number of digits?
Naddik [55]

Answer:

there are only 4 whole numbers whose squares and cubes have the same number of digits.

Explanations:

let 0, 1, 2 and 4∈W (where W is a whole number), then

0^2=0, 0^3=0,

1^2=1, 1^3=1,

2^2=4, 2^3=8,

4^2=16, 4^3=64.

You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits







7 0
2 years ago
What is the value of cos(A) in the diagram?<br> a.60/61<br> b.61/11<br> c.11/61<br> d.61/60
ehidna [41]

Answer:

a. 60/61

Step-by-step explanation:

With reference angle A

base(b) = 60

hypotenuse (h) = 61

Now

Cos(A) = b / h

= 60/ 61

3 0
3 years ago
Read 2 more answers
A bag contains 50 blue marbles and 66 red marbles. If 88 more red marbles are added to the bag, how many more blue marbles must
vaieri [72.5K]

Answer:

60

Step-by-step explanation:

After adding 88 red marbles, there are 50 blue marbles out of the 204 marbles total.

Let the number of blue marbles to be added be x.

\frac{50+x}{204+x}=\frac{5}{12} \\ \\ 600+12x=1020+5x \\ \\ 420=7x \\ \\ x=60

7 0
11 months ago
Other questions:
  • Help Please, anyone good at domain values of composite functions.
    13·1 answer
  • The measures of two complementary angles are m angle 1 = (10x+7) and m angle 2=(9x-12) find the measures of both angles
    9·1 answer
  • Please help! Thank youu
    8·1 answer
  • Find x, if the perimeter is 106 <br> 3x+6<br> 2x-3
    11·1 answer
  • Helppppppp pleaseeeeee
    9·1 answer
  • PLEASE HELP!!!! 69 points my guy!!!
    11·1 answer
  • Use the expression below<br> 5a - 2 - 3 + 2b - 6a<br><br> Write an equivalent expression
    12·2 answers
  • Name the property of real numbers illustrated by the equation (x + 8) + 4 = x + (8 + 4)
    15·2 answers
  • Please help I need it BAD
    9·2 answers
  • I’ll give Brainliest!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!